What will be the output of the following Arduino code?

निम्नलिखित Arduino कोड का आउटपुट क्या होगा?

#define X 10;
void setup(){
X=0;
Serial.begin(9600);
Serial.print(X);
}
void loop(){
//Do nothing...
}

0xAB

0xa

Error

Explanation

The given Arduino code contains an issue in the way the macro #define X 10; is defined.

Code Breakdown:

#define X 10;
void setup(){
    X = 0;  // Trying to assign a value to X
    Serial.begin(9600);
    Serial.print(X);
}
void loop(){
    // Do nothing...
}

Issue:

The #define directive creates a macro replacement, but the semicolon (;) at the end of #define X 10; is incorrect. It will cause the preprocessor to insert a semicolon after the value 10, leading to an issue when trying to assign a value to X in the setup() function.
You cannot assign a value to X since X is treated as a constant.