The given C code is:

int main () 
{ 
    int xyz(4) = [10, 20, 30, 40]; 
    printf("%d", xyz(1)); 
}

Explanation:

1. Array Declaration: The code attempts to declare an array as int xyz(4) = [10, 20, 30, 40];.

   • The correct way to declare an array in C is by using square brackets, not parentheses.
   • It should be int xyz[4] = {10, 20, 30, 40};.

2. Accessing Array: The code tries to access the array using xyz(1), which is incorrect. The correct way to access the array is xyz[1], not xyz(1).

So, there are syntax errors in both the declaration and the way the array is accessed.

Correct Answer:

(B) Compile error