Let's analyze the given Python code step by step:

def gfg(x, l=[]):
    for i in range(x):
        l.append(i * i)
    print(l)

gfg(2)

1. Function gfg:

   • It takes two parameters: x and l. l has a default value of an empty list [].
   • Inside the function, a loop runs from 0 to x-1 (inclusive). In each iteration, it appends i*i (the square of i) to the list l.

2. Calling gfg(2):

   • x = 2 and l uses the default value [] (an empty list).
   • The loop will run for i = 0 and i = 1:
     • When i = 0: 0*0 = 0, so 0 is appended to the list.
     • When i = 1: 1*1 = 1, so 1 is appended to the list.

3. Final result: After the loop, the list l will contain [0, 1] and that will be printed.

Output:

(B) [0, 1]

Explanation:

• Since the list l starts empty and the loop runs twice (for i = 0 and i = 1), the final list becomes [0, 1].

• • range(2) का मतलब है 0 और 1। i*i करने पर 0*0=0 और 1*1=1 लिस्ट में जुड़ेंगे।

Correct Answer: B) [0, 1]